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What average force is required to stop a 120 kg football player running at 8 m/s in a time of 0.4 s

Ch 7: Momentum & Impulse Flashcards Quizle

An 80-kg football player travels to the right at 8 m/s and a 120-kg player on the opposite team travels to the left at 4.0 m/s. a person's momentum could be reduced from 2000 kg m/s to zero in just 0.1 s. If this occurs, the average force exerted to stop the person is. The average force required to accelerate a .20-kg ball from rest to. What is the force required to accelerate an object with a mass of 20 kg from stationary to 3 m/s 2? F = m * a. F = 20 kg * 3 m/s 2. F = 60 N. Newtons are a derived unit, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared. Further Reading. Newton's Second Law. A 200 kg football player is running toward another player at 12 m/s. How much average force needs to be applied over 2.0 seconds to bring him to a stop? A 833 N ? ? 1,200 N ? ? 1,125 N O D 985 N O Need to know the other player's mass to solve this proble Average Force Calculator. Here is the online physics calculator to find the average force exerted by an object. Enter the mass of the object, final velocity, initial velocity, the time period for which the force is exerted in this online average force calculator and submit to know the force in Newtons The force needed is 400 Newtons. Explanation: The force can be determined by means of Newton's law. (1) Where F is the force needed to stop the football player, m is the mass of the football player and a is the acceleration. However, 1N = 1 kg.m/s^{2} Hence, the force needed is 400 Newtons

Example 8.1 (a) Calculate the momentum of a 110-kg football player running at 8.00 m/s. (b) Compare the player's momentum with the momentum of a hard-thrown .410-kg football that has a speed of 25.0 m/s How much force is needed to stop a 80-kg football player if he decelerates at 5 m/s2 Get the answers you need, now! Prestonboatman Prestonboatman 12/12/2016 Physics Middle School How much force is needed to stop a 80-kg football player if he decelerates at 5 m/s2 1 See answer Prestonboatman is waiting for your help. Add your answer and earn. The dog's average velocity, vavg = 5m/s; the time, t = 12 seconds. F = m (v f - v i)/t . F = 10 kg (5 m/s - 0 m/s) / 12 sec. F = 50 kg m/s / 12 sec. F = 4.166 kg m/s 2 = 4.166 Newtons. 2) A 5kg ball is rolled for 15 seconds at an average velocity of 7 m/s. What is its average force? Answer: The mass of the ball, m = 5 kg. The time t = 15 s. The. A force F applied to an object for a time Δt gives rise to a change in momentum of the object. Meaning of the Impulse Defined Above You need to stop a 0.4 Kg ball that has a speed of 20 m/s. What force is needed to stop this ball in a) 1 s b) 0.1 s c) 0.01 s Solutions F Δt = m Δv = m (vf - vi) , we need to stop the ball, hence vf = 0, vi. m - mass in kilograms [kg] v - velocity in metres per second [m/s] Example calculation. Let's think of the case of an object with a mass of 150 kg moving at a velocity of 5 m/s. The kinetic energy equation will be: KE = 150 x 5 2 / 2. and the result: The kinetic energy for the above data is 1875 J. This is equal to: 1.875 kJ; 0.

Example 8.1 Calculating Momentum: A Football Player and a Football (a) Calculate the momentum of a 110-kg football player running at 8.00 m/s. (b) Compare the player's momentum with the momentum of a hard-thrown .410-kg football that has a speed of 25.0 m/s. Strateg Football player A has a mass of 210 pounds and is running at a rate of 5.0 mi/hr. He collides with player B. Player B has a mass of 190 pounds and is running in the same direction at 3.0 mi/hr. The force required to pull the box at a steady rate is 78 N. What is the coefficient of friction? 0.52. A 52.0-kilogram skateboarder does a. Would this force be enough to lift a person off the ground? 130 N, no this is not enough to lift a person. 4. How much force is required to stop a 60 kg person traveling at 30 m/s during a time of a. 5.0 seconds 360 N b. 0.50 seconds 3600 N c. 0.05 seconds 36000 N. 5. A loaded train freight car (10,000 kg) rolls at 2 m/s East towards another. A football player picks up.the football runs with it and throws it to a teammate, during which of these actions is work being done on the football? Physics. A football player of mass 103 kg running with a velocity of 2.0 m/s [E] collides head-on with a 110 kg player on the opposing team travelling with a velocity of 3.2 m/s [W]

the change in time is Δ t. The Average Force Formula aids one in getting the rate of change of momentum for any number of time intervals (Δ t). Expressed in Newton (N). Solved Examples. Example 1: A child throws bowling ball having a mass of 5 kg and it rolls with a velocity of 4 m/s for 1 s. Compute its average force? Answer: Known: Mass of. A 0.50 kg football is thrown with a velocity of 15 m/s to the right. A stationary reciever catches the ball and brings it to rest in 0.020 s. Plug in F(.020 s) = (0.50 kg)(15 m/s). F = 375 N = 3.8 * 10^2 N to the right. (Table of contents) 2. An 82 kg man drops from rest on a diving board 3.0 m above the surface of the water and comes to.

Force Calculator F = m

1. A 95-kg football player traveling 5.0 m/s is stopped in 1.0 s by a tackler. a. What is the original kinetic energy of the player? b. What average power is required to stop him
2. Momentum, mass, velocity calculator. Enter 2 values to convert and calculate the third, momentum, mass or velocity. Free online physics calculators, velocity equations and density, mass and volume calculators
3. How much force is required to stop a 1200 kg car in 2 seconds if the car is traveling at a speed of 33 m/s? (First calculate acceleration.) 6. During a 10 second interval, a bus increases its speed from 30 m/s to 36 m/s. If the force applied to the bus is 12 500 N, what is the mass of the bus? (First calculate acceleration.) 7. A force applied.
4. A) 200. kg m/s B)50.0 kgm/s C) 20.0 kg m/s D) 12.5 kg m/s 1.A 5.00-kilogram block slides along a horizontal, frictionless surface at 10.0 meters per second for 4.00 seconds. The magnitude of the block's momentum is A) speed of the box B)mass of the contents of the box C) magnitude of the horizontal force applied to the bo

The average football sack can produce a bone-shattering 1600 lbs of force. Armed with new tools, researchers are now studying the science of a gridiron fundamental: The tackle A 92.0 kg football player running at 6.50 m/s north collides with an 85.0 kg football player running at 6.00 m/s south. The 92.0 kg football player continues moving at a velocity of 2.00 m/s after the collision A force acting upon an object for some duration of time results in an impulse. The quantity impulse is calculated by multiplying force and time. Impulses cause objects to change their momentum. And finally, the impulse an object experiences is equal to the momentum change that results from it Calculate the final speed of a 110-kg rugby player who is initially running at 8.00 m/s but collides head-on with a padded goalpost and experiences a backward force of $$\displaystyle 1.76×10^4N$$ for $$\displaystyle 5.50×10^{-2}s$$. 39. Water from a fire hose is directed horizontally against a wall at a rate of 50.0 kg/s and a speed of 42. A 5.50-kg bowling ball moving at 9.00 m/s collides with a .850-kg bowling pin, which is scattered at an angle to the initial direction of the bowling ball and with a speed of 15.0 m/s. Calculate the final velocity (magnitude and direction) of the bowling ball. Is the collision elastic

An 85 kg football player traveling 4.7 m/s is stopped in 1.0 s by a tackler. a) What is the original kinetic energy of the player? b) What average power is required to stop him Calculate the final speed of a 110-kg rugby player who is initially running at 8.00 m/s but collides head-on with a padded goalpost and experiences a backward force of $1.76\times 10^{4}\textrm{ N}$ for $5.50\times 10^{-2}\textrm{ s}$ F_avg=375N The average force exerted can be calculated using the following equation: F_avg=(Deltap)/(Deltat) Where Deltap is the change in momentum and Deltat is the change in time. We are given the following information: |->m=0.50kg |->v_i=15 m//s to the right |->v_f=0 |->Deltat=0.020s Momentum is given by vecp=mvecv. Therefore, the change in momentum Deltap is: Deltap=p_f-p_i. Force Calculator The force can be calculated by using the following formula: where p is the momentum, t is the time, m is the mass and a is the acceleration. Mass (m) A 98 kg fullback is running along at 8.6 m/s when a 76 kg A football player runs at 8 m/s and plows into an 80 kg referee standing on the field. The player hits the referee and stops immediately after the explosion a fragment of mass 10 kg has a velocity of 120 m/s straight downward. How high above the poin

Since this formula requires the use of kilograms, we convert the 14.5 ounces to 0.411kg. To figure out the force of the football that I threw, we will plug in our variables of mass (0.411kg) and acceleration (18.5m/s^2). Force=(m)(a) Force=(0.411kg)(18.5m/s^2) Force=7.6035N Therefore the force of the ball that I threw was 7.60 Average acceleration is the change in speed divided by the change of time, and is the how an object's movement changes with time, on average. Instantaneous acceleration is the derivative of speed with respect to time, or the limit of the average acceleration over an infinitesimal period of time. It is used to find the exact acceleration of an. A force of 120 N is applied to the front of a sled at an angle of 28.0 above the horizontal so (1250 kg)(26 m/s)2 = 422,500 J 8. What will be the kinetic energy of a bullet, which has a mass of 22.0 grams, moving with a What is the magnitude of the force F required to push the crate to the top of the incline at

Solved: A 200 Kg Football Player Is Running Toward Another

• What average power is required for a runner with a mass of 80 kg to reach a speed of 8.2 m/s during a time of 1.8 s? View Answer A 200 pound boy lifts a 40 kilogram box off of the floor 1.3 meters.
• a. equal to 0.4, exactly. b. greater than 0.4 but less than 0.8. c. less than 0.4. ~ greater than or equal to 0.4 e J less than 0.4 but greater thanO.25 f. None of the above completions yields a true statement. 24. Which of the following is not a vector quantity? a. force b. acceleration c. weight d. velocity e displacement f
• a momentum of 5 kg·m/s and bounces back with a momentum of 6 kg·m/s after the collision with the racket. What is the change in momentum of the tennis ball? A. 1 kg·m/s B. 5 kg·m/s C. 6 kg·m/s D. 11 kg·m/s E. 0 kg·m/s 20. A rubber ball moving with an initial momentum P i collides elastically with a vertical wall
• 2.6 Physics in action: Impulse (ESCJM). A very important application of impulse is improving safety and reducing injuries. In many cases, an object needs to be brought to rest from a certain initial velocity
• The amount of work done by a force to displace an object is found from the equation. W = F*d*cos(Theta) The force required to raise the car at constant speed is equivalent to the weight (m*g) of the car. Since the 2400-kg car weighs 2X as much as the 1200-kg car, it would require twice as much work to lift it the same distance
• C) 15.0 kg G) 40 kg D) 20.0 kg H) 50 kg 11. A football player kicks a .41-kg football initially at rest; and the ball flies through the air. If the kicker's foot was in contact with the ball for 0.051 s and the ball's initial speed after the collision is 21.0 m/s, what was the magnitude of the average force on the football? A) 9.70 N E) 135 N.
• utes

Average Force Calculator - Easycalculation

Consider this elastic collision between two spheres. They collide and then bounce apart. Sphere A has a mass of 8-kg. Sphere B has a mass of 5-kg. Before the collision, Sphere A is travelling to the right at 3 m/s and Sphere B is travelling to the left at 4 m/s. After the collision, Sphere A is travelling 2 m/s The average force the oor exerts on the oor is then F~ = P t = 4:40 0:07 ~j = 62:9~j with maginutude 62.9 N and direction up. 0.7 A tennis player receives a shot with the ball (0.060 0 kg) traveling horizontally at 59.5 m/s and returns the shot with the ball traveling horizontally at 37.5 m/s in the opposite direction. (Assume the initia Initial velocity (u) = 5 m/s. Terminal velocity (v) = 8 m/s. Time period (t) = 6s. Now, initial momentum (m × u) = 100kg × 5m/s = 500 kg.m.s-1. Final momentum (m × v) = 100kg × 8m/s = 800 kg.m.s-1. Therefore, the object accelerates at 0.5 ms-2. This implies that the force acting on the object (F = ma) is equal to: F = (100kg) × (0.5 ms-2.

How much force is needed to stop an 80-kg football player

Get homework help fast! Search through millions of guided step-by-step solutions or ask for help from our community of subject experts 24/7. Try Chegg Study today Search the world's information, including webpages, images, videos and more. Google has many special features to help you find exactly what you're looking for

constant speed of 10 m/s. At B, the car encounters an unbanked curve of radius 50 m. The car follows the road from B to C traveling at a constant speed of 10 m/s while the direction of the car changes from east to south. 23. What is the magnitude of the acceleration of the car as it travels from A to B? (a) 2 m/s 2 (c) 10 m/s 2 (e) zero m/s Il servizio gratuito di Google traduce all'istante parole, frasi e pagine web tra l'italiano e più di 100 altre lingue a 15-newton force acts on a 2.0-kilogram mass. The work done over time is summarized in the table shown. DATA TABLE Time (s) Work (J) 0 0 1.0 32 2.0 59 3.0 89 4.0 120 a) Using the information in the data table, construct a graph on a grid, following the directions given. 1) Develop an appropriate scale for work and plot the points for a work.

1. A car moving at 10 m/s speeds up uniformly to a speed of 30 m/s in a time of 5 seconds. What was the car's acceleration? Answer: 4 m/s2 2. A bus is moving at a speed of 20 m/s, when it begins to slow at a constant rate of 5 m/s2 in order to stop at a bus stop. If it comes to rest at the bus stop, how fa already know that the ball is about 0.4 kg. Now, we just need to find the acceleration of the ball, which is the change in velocity of the ball. The ball starts with no speed and ends up at about 30 m/s, in about 0.01 sec-onds. So 5 a = − = 30 0 0 01 3000 2 m/s m/s s m. s Step 2: Let's use the given to substitute on the formula: SA = 2 (WL + HL + HW) SA = 2 ((3 cm x 5 cm) + (4 cm x 5 cm) + (4 cm x 3 cm)) SA = 2 (15 cm² + 20 cm² + 12 cm²) SA = 2 (47 cm²) SA = 94 cm² . Answer: The surface area of a rectangular box of 5 cm long, 3 cm wide and 4 cm wide is 94 cm. a=(9.8 m/s - 0 m/s)/(2 s - 0 s) a= 4.9 m/s 2. As he runs with the flow of the play (e.g. to the right), he maintains constant speed (a = 0). When he sees an opening in the line, he plants his foot to stop his motion to the right, changes direction and accelerates upfield into the open. By planting his foot, he applies force to the turf. The.

Luckily, Prepterminal's Inductive Reasoning guide offers a methodological approach to identifying and solving such questions in optimal time. SHL Situational Judgement Practice Test The SHL Situational Judgement Test is designed to take a close look at a candidate's personal qualities in a work environment This equation is an analog to the definition of linear momentum as p = mv.Units for linear momentum are kg ⋅ m/s while units for angular momentum are kg ⋅ m 2 /s. As we would expect, an object that has a large moment of inertia I, such as Earth, has a very large angular momentum.An object that has a large angular velocity ω, such as a centrifuge, also has a rather large angular momentum We aimed to improve the physical capacity of a top-level elite football team during its pre-season by implementing a maximal strength and high-intensity endurance training program. 21 first league.

OpenStax College Physics Solution, Chapter 8, Problem 33

Google's free service instantly translates words, phrases, and web pages between English and over 100 other languages Truck with a mass of 2250 kg moving with a velocity of 25 m/s C) ith a mass of 1210 kg moving at a velocity of 51 m/s (e I C) c. Truck with a mass of 6120 kg moving at a velocity of 10 m/s (Q I / 'ZOO ) S d. Car with a mass of 1540 kg moving at a velocity of 38 m/s S 11. A rubber ball with a mass of 0.30 kg is dropped onto a steel plate Water from a fire hose is directed horizontally against a wall at a rate of 50.0 kg/s and a speed of 42.0 m/s. Calculate the force exerted on the wall, assuming the water's horizontal momentum is reduced to zero

15. Velocity-Time Graph Sketch a velocity-time graph for a car that goes east at 25 m/s for 100 s, then west at 25 m/s for another 100 s. 16. Average Velocity and Average Acceleration A canoeist paddles upstream at 2 m/s and then turns around and floats downstream at 4 m/s. The turnaround time is 8 s. a. What is the average velocity of the canoe (a) Find the useful power output of an elevator motor that lifts a 2500-kg load a height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2500 kg is raised in height, but the full 10,000 kg is accelerated The piano starts at 17.28 m/s and ends at 0 m/s. This means that the average velocity would be (17.28 m/s)/2. Since I know the time interval, I can calculate the change in vertical position so we saw last time that there's two types of kinetic energy translational and rotational but these kinetic energies aren't necessarily proportional to each other in other words the amount of translational kinetic energy isn't necessarily related to the amount of rotational kinetic energy however there's a whole class of problems a really common type of problem where these are proportional so.

v0 = 0 m/s v = 24 m/s a = 4.9 m/s/s (24 m/s)^2 = (0 m/s)^2 + 2(4.9 m/s/s)d 578 m^2/S^2 = d 9.8 m/s/s d = 58.7755 c) For this part of the problem I will redraw my x axis along the horizontal, and my y axis along the vertical. It is coming down at an initial angle of 30 degrees to the horizontal with a speed of 24 m/s. When that speed is broken. The average mass of a skier is 70 kg and the average speed of the lift is 75 m/min. Determine (a) the average power required, (b) the required capacity of the motor if the mechanical efficiency is 85 percent and if a 300 percent overload is to be allowed.It takes 15 s to raise a 1200-kg car and the supporting 300kg hydraulic car-lift platform.

how much force is needed to stop a 80-kg football player

A football player kicks a ball with a force of 50N. Find the impulse on the ball if his foot stays in contact with the football for 0.01s. A hockey player applies an average force of 80N to a 0.25kg hockey puck for a time of 0.2s. Determine the impulse An 8.00 kg object is moving at 4.00 m/s. a) Find the initial momentu For multiple bounces, it's just like dropping the ball again from a reduced height. If the first height is h, the second will be f*h, the third f*f*h, the fourth f*f*f*h, and so on. So if f is 0.9, the first bounce will be 0.9 times as high, the second 0.81 times as high, the third 0.729 times as high (as the original height), and so on A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 20.0 m/s by a 6250 N braking force acting opposite the car's motion. Use the impulse-momentum theorem to answer the following questions moving at 5 m/s. It has momentum of 50 kg*m/s. Since friction does not act, the momentum will remain 50kg*m/s (Newton's law). Suppose at some later time it has filled up with 10kg of rain, so now the cart has a mass of 20kg. It still has the 50kg*m/s of momentum, so it must be moving at 2.5m/s, which means it has decreased due t let's say you and I are playing a game where we're trying to figure out how high a ball is being thrown in the air or how fast that we're throwing that ball in the air and what we do is one of us has a ball and the other one has a stopwatch over here so this is my best attempt to it looks more like a cat but a stopwatch but I think you get the idea and what we do is one of us throws the ball.

There is also a report on the time it takes you to travel certain distances. This report shows you min:sec per kilometre, seconds per 100 metres and seconds per metre. - especially for the athlete we a conversion to the times for all track distances from 100m through to 10,000 m (10k) 35 m/s POINT C: The speed before impact would be the hypotenuse of the triangle formed by the initial horizontal velocity, v xo and the final vertical velocity, v yf. We know the horizontal velocity is v xo = 15 3 m/s. The vertical velocity at when the projectile hits the ground can be obtained from v y = v yo - gt = 17 - 10(4.68 s) = -29. let's talk about how to handle a horizontally launched projectile problem these technically speaking if you already know how to do projectile problems there's nothing new except that there's one aspect to these problems that people get stumped by all the times I'm going to show you what that is in a minute so that you don't fall into the same trap what we mean by a horizontally launched. OpenStax solutions on video for the College Physics and College Physics for AP Courses textbooks by OpenStax. Step by step solution manual by screencast video with calculator screenshots. Created by the expert physics teacher Shaun Dychko 2(14.8−0) ⇒a x=−8.97m s2.! (b)Similarly!along!the!vertical!direction,!v y 2=v oy 2+2a y (y−y o)⇒a y= v y 2−v oy 2 2(y−y o).! Plugginginthevalues, a y= (2.7)2−(0.977)2 2(0.878−1.6) ⇒a y=−4.39m s2.! (c)Using!the!kinematic!equation,!v x=v ox+a x t⇒t= v x−v ox a x = 36.2−39.7 −8.97 ⇒! t=0.390s.! Noticethat.

Average Force Formula - Softschools

• d while running is that he wants to be at a maximal speed when he reaches the take off board and the point of take off. Since velocity is a direct measure of speed over time, in order for the jumper to reach a high velocity, he must enter his jump at a high speed (Huremović, 2009)
• 54 m/s after a ball-on-bat contact time of .03 s. What force is exerted on the .15 mass 105 kg, is running north at 11 m/s. He is tackled in an inelastic collision by Refrigerator Perry, mass 155 kg, running south at 4 m/s. m = 0.4, find the speed of the bullet before impact
• The North American Aviation P-51 Mustang is an American long-range, single-seat fighter and fighter-bomber used during World War II and the Korean War, among other conflicts.The Mustang was designed in April 1940 by a design team headed by James Kindelberger of North American Aviation (NAA) in response to a requirement of the British Purchasing Commission
• It's a velocity of about 20 m/s. Well, it will still hurt when it impacts a body, but it definitely won't cause anything worse than a bruise. The ship weighs 50,000 tons and can move at the speed of 10 knots. We can always use speed converter to find that it's around 5.1 m/s. Its kinetic energy is then roughly 661 MJ. That number is obtained.
• Therefore Terry had done a lot of work in order to throw for 90 yards. To find out how much power was needed we will use the formula, P = W/t (where 'P' represents power (watts), 'W' represents work (joules) and 't' represents the time taken (s). The time taken for this pass was 8 seconds. P = W/t, P = 106,984.8/8
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• The average velocity formula and velocity units. The average velocity formula describes the relationship between the length of your route and the time it takes to travel. For example, if you drive a car for a distance of 70 miles in one hour, your average velocity equals 70 mph. In the previous section, we have introduced the basic velocity equation, but as you probably have already realized.

Forces, Impulse and Changes in Momentu

Introduction . The Department of Justice published revised regulations for Titles II and III of the Americans with Disabilities Act of 1990 ADA in the Federal Register on September 15, 2010. These regulations adopted revised, enforceable accessibility standards called the 2010 ADA Standards for Accessible Design 2010 Standards or Standards A) 5 m/s B) 10 m/s C) 20 m/s D) 40 m/s E) 100 m/s 28.A 100 W motor propels an object with a mass of 4 kg for 2 s from rest. Its final velocity will be A) 16 J B) 64 J C) 128 J D) 256 J E) 512 J 29.An object with a mass of 2 kg increases in speed from 4 m/s to 12 m/s in 3 s. The total wor

Kinetic Energy Calculato

Consider a baseball of mass 145 gm and diameter 73 mm. If we take C D = 0.5 at low ball speeds then with A = 0.00418 m 2 and d = 1.21 kg/m 3, the drag force is F D = 0.00127 V 2 (Newton) while the gravitation force is mg = 0.145 x 9.8 = 1.42 Newton. At a ball speed V = 7 m/s, the drag force is only 0.062 Newton, 23 times smaller than the. The aim of this study was to describe in the way teams played for the last eight seasons (from 2011-12 to 2018-19) in the Spanish Football First Division (Spanish LaLiga Santander), taking into. In physics terms, acceleration is the amount by which your velocity changes in a given amount of time. In terms of equations, it works like this: Given initial and final velocities, vi and vf, and initial and final times over which your speed changed, ti and tf, you can also write the equation like this: [ Due to more time taken to stop the ball, the rate of change of momentum of ball is decreased and hence a small force is exerted on the hands of player. So, the hands of player do not get hurt. m = 0.4 kg, u = 10 m/s Calculate the force on the object in time interval 0 to 3 s. (b) Calculate the force on the object in the time interval 6.

Solved: Using mass and speed data from Example 8

Whether you're stuck on a history question or a blocked by a geometry puzzle, there's no question too tricky for Brainly. Adriana2345. Mathematics; 5 points; What is the value of 6(2b-4) when b = 5? Get help. Our community of experts consists of students, schoolteachers, PhDs, and other geniuses just waiting to tackle your toughest questions 1. A rock is thrown horizontally off the roof of a building at 18 m/s. What is the horizontal component of the velocity just before the rock hits the ground? (A) -18 m/s (B) -9.8 m/s (C) 9.8 m/s (D) 18 m/s 2. A juggler throws a ball at 0.22 m/s at an angle of 60.0o above the horizontal. What is the y-component of the velocity of the ball? (A) 0. Assume that an average passenger has mass 65.0 kg. 6.57.. A ski tow operates on a slope of length 300 m. The rope moves at and provides power for 50 riders at one time, with an average mass per rider of 70.0 kg. Estimate the power required to operate the tow. 6.58.. The aircraft carrier John F. Kennedy has mas Science Test 1 Flashcards Quizle

• Unless otherwise indicated, whenever a numerical value of g is required, take g = 9.8 m s-2 and give your answer to either 2 significant figures or 3 significant figures. Figure 1 A car moves along a straight horizontal road. At time t = 0, the velocity of the car is U -m s 1
• In 4 years from now, Raymond will be 6 years older than his sister, and, AT THE SAME TIME, will be twice as old as she. Then it becomes clear that in 6 years Raymond is 12 years old, while the sister is 6 years old. So, now their current ages are 12-4 = 8 years (Raymond) and 6-4 = 2 years (the sister). ANSWE
• or 8.5 m/s. The projectile would have a Y-velocity of v 0y 20sin65 or 18 m/s. So, the projectile would fire as far as one fired horizontally at 8.5 m/s and as high as one fired straight up at 18 m/s. 5. A lacrosse player slings the ball at an angle of 30 degrees above the horizontal with a speed of 20 m/s. + x y cos v 0y T v 0 sinT V 0 V 0 V 0y.
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• We know that Force = Impulse/ Time . Impulse = mass * change in velocity Time = 0.01 s Mass m = 150 g = 1.5 x 10 ̄ ¹ kg Change in velocity = Final - intial velocity = 20 - (-12) = 32 m/s Therefore Force = mass * change in velocity / time = 1.5 x 10 ̄ ¹ x 32 / 0.01 = 15 x 32 = 480 N Average force on the ball is 480

Learn how to do just about everything at eHow. Find expert advice along with How To videos and articles, including instructions on how to make, cook, grow, or do almost anything UPS Freight Less-than-Truckload (LTL) transportation services are offered by TFI International Inc., its affiliates or divisions (including without limitation TForce Freight), which are not affiliated with United Parcel Service, Inc. or any of its affiliates, subsidiaries or related entities (UPS) Fitness Testing > Tests > Aerobic Endurance > Beep > Table. Beep Test Calculations. Here is a table of the number of shuttles required to run for each level of the beep test, with calculations for the speeds, times and distances for each level Get 24/7 Assignment/Homework help on Transtutors.com. 600,000+ Classroom Assignments. 20,000+ Experts. 30% Discount. 5 Mins Response Time. Ask Now 0.4. 0.4 A racing car travels on a circular track of radius 275 m. Suppose the car moves with a constant linear speed of 51.5 m/s. • a)Find its angular speed. • b)Find the magnitude and direction of its acceleration. a) Angular and linear speed are always related through : v= r!! = v r = 51:5 275 = 0:19 rad=

Because force is a component of work and an impact is the conversion of energy into work, you can use the equations for energy and work to solve for the force of an impact. The distance traveled when the work is accomplished by an impact is called the stop distance. It is the distance traveled by the moving object after the impact has occurred 3.4 m· 62 kg ·9.8 m/s2 +( 3.4 m−( 5.0 m)/2) 52 kg ·9.8 m/s2 ~τ l = 2.10 kN Since this sign of the answer is positive and counter-clockwise is positive, the this force must point downward. Likewise, to determine the magnitude and direction of the right support, we place the axis at the left support. The sum of the torques is then X ~τ. Andrews University :: A Southwest Michigan Christian. and negative for clockwise rotation. The magnitude of the body's angular velocity is the angular speed. Angular AccelerationIf the angular velocity of a body changes from v 1 to v 2 in a time interval t t 2 t 1, the average angular acceleration a avg of the body is (10-7) The (instantaneous) angular acceleration a of the body is (10-8) Both a.

(4 ed) 7.6 A 1,500-kg car accelerates uniformly from rest to 10 m/s in 3.0 s. Find (a) the work done on the car in this time, and (b) the average power delivered by the engine in the first 3.0 s m s cos40.0 10.0 (9.80 / ) 2 1 2 2. From this, vi = 10.7 m/s 8. When baseball players throw the ball in from the outfield, they usually allow it to take one bounce before it reaches the infielder on the theory that the ball arrives sooner. Suppose that the angle at which the bounced ball leaves the ground is th Time (s) Velocity vs. Time 3.0 4.0 Velocity (m/s) 25 15 5 0 123 Time (s) Speed vs. Time 45 20. Speed (m/s) 10. Displacement 0 Velocity 0 Time Time (4) Displacement 0 Velocity 0 Time Time (3) ANSWER: (4) 40. m/s 24. The maximum number of components that a single force may be resolved into is ANSWER: (4) unlimited 25. Which quantity has both. a) A recent survey by the alumni of a major university indicated that the average salary of 10,000 of its 300,000 graduates was 125,000. b) The average salary of all assembly-line employees at a certain car manufacturer is $33,000. c) The average late fee for 360 credit card holders was found to be$56.75. 3

Welcome to MLB.com, the official site of Major League Baseball Created Date: 1/13/2011 7:21:28 P h max = (19.8 m / s) 2 / 2 (9.8 m/s 2) h max = 20 m 4.65 A car is parked on a steep incline overlooking the ocean, where the incline makes an angle of 37 o below the horizontal When a baseball is thrown or hit, the resulting motion of the ball is determined by Newton's laws of motion.From Newton's first law, we know that the moving ball will stay in motion in a straight line unless acted on by external forces.A force may be thought of as a push or pull in a specific direction; a force is a vector quantity.If the initial velocity and direction are known, and we can. The normal force describes the force that the surface an object is resting on (or is pressed onto) exerts on the object. For a still object on a flat surface, the force must exactly oppose the force due to gravity, otherwise the object would move, according to Newton's laws of motion

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